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42=1.4r^2
We move all terms to the left:
42-(1.4r^2)=0
We get rid of parentheses
-1.4r^2+42=0
a = -1.4; b = 0; c = +42;
Δ = b2-4ac
Δ = 02-4·(-1.4)·42
Δ = 235.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{235.2}}{2*-1.4}=\frac{0-\sqrt{235.2}}{-2.8} =-\frac{\sqrt{}}{-2.8} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{235.2}}{2*-1.4}=\frac{0+\sqrt{235.2}}{-2.8} =\frac{\sqrt{}}{-2.8} $
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